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Difference between <? super T> and <? extends T> in Java

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If we''re using a class method, we don''t have an instance to call super with. Fortunately for us, super works even with a type as the second argument. --- The type can be passed directly to

''super'' object has no attribute ''__sklearn_tags__''

''super'' object has no attribute ''__sklearn_tags__''. This occurs when I invoke the fit method on the RandomizedSearchCV object. I suspect it could be related to compatibility

coding style

As for chaining super::super, as I mentionned in the question, I have still to find an interesting use to that. For now, I only see it as a hack, but it was worth mentioning, if only for the differences

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Why do this () and super () have to be the first statement in a

The automatic insertion of super () by the compiler allows this. Enforcing super to appear first, enforces that constructor bodies are executed in the correct order which would

Understanding Python super() with init() methods

super() lets you avoid referring to the base class explicitly, which can be nice. But the main advantage comes with multiple inheritance, where all sorts of fun stuff can happen.

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super () in Java

super() is a special use of the super keyword where you call a parameterless parent constructor. In general, the super keyword can be used to call overridden methods,

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The one without super hard-codes its parent''s method - thus is has restricted the behavior of its method, and subclasses cannot inject functionality in the call chain. The one

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I''m currently learning about class inheritance in my Java course and I don''t understand when to use the super() call? Edit: I found this example of code where super.variable is used: class A {

How does Python''s super () work with multiple inheritance?

In fact, multiple inheritance is the only case where super() is of any use. I would not recommend using it with classes using linear inheritance, where it''s just useless overhead.